Question

a train starting from a railway station and moving with uniform acceleration ,attains a speed of 40km/hr in 10 minutes. find acceleration
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Answer 1

Given :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 40 km/h
• Time (t) = 10 minutes

To find :

• Acceleration (a)

According to the question,

Note : At first we have to change 40 km/h into m/s.

• Final velocity (v) = 11.11 m/s

And we have to change time in seconds.

• Time (t) = 600 seconds

By using Newtons first equation of motion,

➞ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

➞ 11.11 = 0 + a × 600

➞ 11.11 - 0 = 600a

➞ 11.11 = 600a

➞ 11.11 ÷ 600 = a

➞ 0.01851 = a

So,the acceleration is 0.01851 m/s².

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More formulas :

Newtons first equation of motion :

• v = u + at

Newtons second equation of motion :

• s = ut + ½ at²

Newtons third equation of motion :

• v² = u² + 2as

Answer 2

Explanation:

Given :

• a train starting from a railway station and moving with uniform acceleration ,attains a speed of 40km/hr in 10 minutes.

To Find :

• find the acceleration

Solution :

Concept :

There are some formulas but the most frequently used formula is

• Acceleration= velocity/time

• Which is derived from

• V= u+at (If u=0).

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$\sf : \implies \: \: \: \: \: speed = \frac{40 \times 1000}{3600} \\ \\ \\ \sf : \implies \: \: \: \: \: speed = \cancel{ \frac{40000}{3600}} \\ \\ \\ \sf : \implies \: \: \: \: \: speed =11.11$

We have :

$: \implies \: \: \: \: \: \: \: \boxed{ \sf Acceleration = \frac{speed}{time} \: }$

Substitute all Values :

$: \implies \: \: \: \: \: \: \: \sf \: \: \underline{ Acceleration} = \frac{11.11}{10 \times 60} \\ \\ \\ : \implies \: \: \: \: \: \: \: \sf \: \: \underline{ Acceleration} = \frac{11.11}{600} \\ \\ \\ : \implies \: \: \: \: \: \: \: \sf \: \: \underline{ Acceleration} =0.0185 \: {ms}^{2}$

• Hence the acceleration is 0.0185 ms²