A train starting from a railway station and moving with uniform acceleration attains a speed of 40km h-¹ in 10 minutrs .find its acceleration.
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Hey !!!
here , initial speed of trail u = 0 [ start from rest ]
final speed of train , v = 40km h -¹
= 40×40m / 60× 60s
= 11 .11 m s-¹
and time taken , t = 10 minutes
= 10 × 60 = 600s
Acceleration a *= v - u / t
a = 11. 11 - 0 / t
a = 11.11- 0/ 600
a = 11. 11 / 600m s-²
a = 0.0185 ms-² [ or ,1. 85× 10-²m s-²]
Hope it helps !!!
#Rajukumar111@@@
here , initial speed of trail u = 0 [ start from rest ]
final speed of train , v = 40km h -¹
= 40×40m / 60× 60s
= 11 .11 m s-¹
and time taken , t = 10 minutes
= 10 × 60 = 600s
Acceleration a *= v - u / t
a = 11. 11 - 0 / t
a = 11.11- 0/ 600
a = 11. 11 / 600m s-²
a = 0.0185 ms-² [ or ,1. 85× 10-²m s-²]
Hope it helps !!!
#Rajukumar111@@@
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