a train starting from a railway station and moving with uniform acceleration attain a speed 40 km per hour in 10 minutes find its acceleration
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u=0 kmph
v=40 kmph
t=10 min=10/60=1/6
a= (v-u)/t=(40-0)/1/6
=40×6=240 km/hr^2
v=40 kmph
t=10 min=10/60=1/6
a= (v-u)/t=(40-0)/1/6
=40×6=240 km/hr^2
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Solution:-
given by :-
》u = 0 , v = 40k/h = 40×5/18 =200/18= 100/9 m/s
》 , t = 10minut = 600s
》by formula:-
》acceleration(a) = (v-u)/t
》 = (100/9-0)/600
》 = 100/5400
》 = 1/54m/s^2
given by :-
》u = 0 , v = 40k/h = 40×5/18 =200/18= 100/9 m/s
》 , t = 10minut = 600s
》by formula:-
》acceleration(a) = (v-u)/t
》 = (100/9-0)/600
》 = 100/5400
》 = 1/54m/s^2
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