A train starting from a railway station and moving with uniform acceleration attends a speed of 40 km per hour in 10 minutes find its acceleration
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Hope u like my process
=====================
Initial speed = 0 km/hr = 0 m/sec
Final speed = 40 km/hr = 400/36 m/sec
= 100/9 m/sec
Time taken = 10 minutes = 600 sec.
So..
Acceleration = (change in speed) /time
= (100/9 - 0)/600 = (100/9) × 1/600
=1/54 m/s² [ =0.018 m/s²]
= 36×360/54 km/hr²
= 2×120 km/hr²= 240km/hr²
_-___-___-___-___-___-___
Hope this is ur required answer
Proud to help you
=====================
Initial speed = 0 km/hr = 0 m/sec
Final speed = 40 km/hr = 400/36 m/sec
= 100/9 m/sec
Time taken = 10 minutes = 600 sec.
So..
Acceleration = (change in speed) /time
= (100/9 - 0)/600 = (100/9) × 1/600
=1/54 m/s² [ =0.018 m/s²]
= 36×360/54 km/hr²
= 2×120 km/hr²= 240km/hr²
_-___-___-___-___-___-___
Hope this is ur required answer
Proud to help you
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