A train starting from a railway station and moving with uniform acceleration attains a speed of 90kmph
in 10min. Find its acceleration.
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Answer:
Final velocity (v) = 40 km/h
v = 40 × (5/18)
v = 11.1111 m/s
Time (t) = 10 minute
t = 60 x 10
t = 600 s
Acceleration (a) =?
Consider the formula
v = u + at
11.11 = 0 + a × 600
11,11 = 600 a
a = 11.11/600
a = 0.0185 ms-2
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