Question

A train starting from a railway station and moving with uniform acceleration attains a speed 72 km/hr in 10 sec. Find its acceleration. ​

Answer 1

Answer:

72km/h = 20m/s

v=20m/s

u = 0m/s

a = v-u/t = 20-0/10 = 20/10 = 2m/s*2

Hope it help you my friend

Answer 2

a train starting from a railway station and moving with uniform acceleration attains a speed 72 km per hour in 10 seconds

So v=72kmph

t=10sec

therefore acceleration(a) =v/t

a=72kmph/10sec

a=72kmph÷1/360 hours

a=72kmph×360hours

therefore a=25920km/hours²