Question

A train starting from a railway station and moving with uniform acceleration attains speed 40 km h^-1 in 10 minutes . find its acceleration

Answer 1

Answer:

a= v-u/t

u = 0

a= 41/10

a= 4km/hr^-2

Answer 2

Given:

• u = 0
• v = 40 km/h = 40 × 5/18 = 11.12m/s
• t = 10min = 10 × 60 = 600s
• a = ?

To Find:

• Find acceleration ?

Solution:

Using 1st equation of motion

v = u + at

→ 11.12 = 0 + a(600)

→ 11.12 = a(600)

→ a = 11.12/600

→ a = 1112/(600 × 100)

→ a = 185.34/10000

→ a = 0.018534 m/s²