Question

A train starting from a railway
station and moving with uniform
acceleration attains a speed
40 km h in 10 minutes. Find its
acceleration.​

Answer 1

Answer:

Good afternoon

Explanation:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.

Final speed of the train, v = 40 km/h = \frac{5}{18}

18

5

× 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ a=\frac{v-u}{t}a=

t

v−u

Solution:-

Putting all the values, we get

⇒ a=\frac{v-u}{t}a=

t

v−u

⇒ a=\frac{11.11-0}{600}a=

600

11.11−0

⇒ a=\frac{11.11}{600}a=

600

11.11

⇒ a=0.0185 \: m/s^2a=0.0185m/s

2

Hence, Acceleration of the train is 0.0185 m/s².