Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h^-1 in 10 min .find its acceleration?​

Answer 1

Answer:

Given

u= 0

V = 40

t = 10min

V= u+at

40 = 0+ a(10)

40= 10a

a = 10mls

Hope this is right

Answer 2

Answer:

→  Hey Mate,

→ Given Question :  A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h^-1 in 10 min .find its acceleration?​

→ Step-by-step explanation:

→ Answer ⇒  u = $0ms^-^1$

         ⇒      v = $40km h^-^1$

         ⇒     v = $\frac{40 X 1000 }{ 60 X 60}$

         ⇒  ∴  = $v =\frac{100}{9} ms^_1$

         ⇒      v = $11.11m s^-^1$

         ⇒    t = 10 minutes

         ⇒    10 × 60

         ⇒  t = 600 sec

         ⇒  a =$\frac{v-u}{t}$

         ⇒      $\frac{11.11 - 0 }{600}$

         ⇒    $\frac{11.11}{600} ms^-^1$

         ⇒ $0.0185ms^-^2$

→ thank you

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