Question

A train starting from a railway station and moving with uniform acceleration attains a speed of 40km /h-¹ in 10 min. Find its acceleration.​

Answer 1

Answer:

Answer Expert Verified

Final speed of the train, v = 40 km/h = × 40 = 11.11 m/s. Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec. Acceleration of the train. Hence, Acceleration of the train is 0.0185 m/s².

Explanation:

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Answer 2

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✤ Required Answer:

✒ GiveN:

• (s) speed = 40km /h-¹
• (t) = 10 min. Find its acceleration.

✒ To FinD:

• Acceleration

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✤ How to solve ?

In the question we have to find The acceleration of train if it attains a speed of 40km /h-¹ in 10 min.

First of all we have to convert speed in m/s and time in sec and for converting into m/s we have to multiply with 5/18 and for sec we have to multiply from 60 .

And by applying the formula of v = u + at we will find acceleration .

Now let's solve it !

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✤ Solution :

$: \Longrightarrow{{\sf{{40km/h \times \dfrac{5}{18} = 11.11m/s }}}}$

$: \Longrightarrow{{\sf{{10m \times 60 = 600s }}}}$

Now by applying the formula ,

$\boxed{\rm{v = u + at}}$

• v = 11.11
• u = 0
• t = 600
• a = ?

$: \Longrightarrow{{\sf{{ 11.11= 0 + a \times 600 }}}}$

$: \Longrightarrow{{\sf{{ 11.11= 600 a }}}}$

$: \Longrightarrow{{\sf{{ a = \dfrac{11.11}{600} }}}}$

$: \Longrightarrow{{\sf{{a = \blue{0.0185 m/s^{-2}}}}}}$

☀️ Hence, solved !!

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