Question

A train starting from a Railway Station and moving with uniform acceleration attains a speed of 40 km/h in 10 minutes. Find its acceleration.

Answer 1

Given :

$Initial \: \: velocity = (u )= 0 \\ Final \: \: velocity = (v )= 40 \: {kmh}^{ - 1} = 11.11 \: {ms}^{ - 1} )\\ Time = (t) = 10 \: minutes \: = 60 \times 10 = 600s \\ Acceleration = (a) = ? \\ \\ We \: \: know \: \: that \: \\ v = u + at \\ 11.11 = 0 + a \times 600 \\ a = \frac{11.11}{600} = 0.0185 {ms}^{ - 1} \\ \\ (0.0185 \: {ms}^{ - 1} = {0.0666 \: kmh}^{ - 1} )$

Answer 2

Hii,

Here

Initial velocity (u) = 0

Final velocity (v)=40km/hr

= 40 multiple by 5/18 m/s

= 100/9

=11.11 m/s

Time (t) = 10 min

= 10 multiple with 60 s

= 600 s

Therefore

Acceleration = final velocity — initially velocity / time taken

=11.11 — 0 / 600 m/s sq

= 0.0185 m/s sq

Thanks