Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40kmh^-1 in 10 minutes . Find its acceleration

Answer 1

Final velocity (v)=40km/hr

= 40 multiple by 5/18 m/s

= 100/9

=11.11 m/s

Time (t) = 10 min

= 10 multiple with 60 s

= 600 s

Therefore

Acceleration = final velocity — initially velocity / time taken

=11.11 — 0 / 600 m/s sq

=0.018516 m/s sq

Answer 2

Initial velocity (u) = 0m/s

Final velocity(v) = 40km/h
= 40 ×5/18
= 100/9 = 11.11m/s


Time(t) = 10 min
= 10×60 = 600 sec

acceleration = v-u/t
= 11.11 - 0/600
= 0.0185m/s²