Question

a train starting from a railway station and moving with uniform acceleration attains a speed 40 km per hour in 10 minutes find its acceleration

Answer 1

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➧ u ➾ 0

➧ t ➾ 10 min = 600s

➧ v ➾ 40 km/h
   ➾ 4000 / 3000
   ➾ 11.11 m s-¹

❱ a ➾ v - u / t
 a ➾ (11.11 - 0) / 600
   ➾ 0.185 m s-² ...✔

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Answer 2

Answer:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time  

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.

Final speed of the train, v = 40 km/h = $\frac{5}{18}$ × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ $a=\frac{v-u}{t}$

Solution:-

Putting all the values, we get

⇒ $a=\frac{v-u}{t}$

⇒ $a=\frac{11.11-0}{600}$

⇒ $a=\frac{11.11}{600}$

⇒ $a=0.0185 \: m/s^2$

Hence, Acceleration of the train is 0.0185 m/s².