a train starting from a railway station and moving with acceleration of 40km per hour in 10minutes find the acceleration
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Answered by
3
u =0
v = 40km/h^2 = 40×1000/3600=11.11
time = 10min = 10×60= 600s
v= u+at
11.11 = 0+a×600
11.11/600=a
0.018 m/s^2=a
v = 40km/h^2 = 40×1000/3600=11.11
time = 10min = 10×60= 600s
v= u+at
11.11 = 0+a×600
11.11/600=a
0.018 m/s^2=a
Answered by
0
Answer:
Explanation:
u=0
v= 40 X 3.6 = 11.1111
a = uniform
Formulae of acceleration is
a = u-v/t
a = 11.111-0 /10 X 60
a = 11.111/600
a = 0.01851851851
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