a train starting from a railway station and moving with uniform acceleration attains the spees of 40 km/hr in 10min find its acceleration
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Intial Velocity Of train(u)=0 m/s
Final Velocity (v)=40 km/h
Convert it into m/s
40 km/h=40×5/18
=11.11 m/s (aprrox=11 m/s)
10 minutes in second=10×60=600 seconds.
Now
Intial Velocity (u)=0 m/s
Final Velocity (v)=11 m/s
Time (t)=600 seconds
Accerlation (a)=?
Use Equation of Motion
v=u+at
11=0+600a
600a=11
a=11/600
a=0.018 m²
Accerlation=0.018 m/s²
Final Velocity (v)=40 km/h
Convert it into m/s
40 km/h=40×5/18
=11.11 m/s (aprrox=11 m/s)
10 minutes in second=10×60=600 seconds.
Now
Intial Velocity (u)=0 m/s
Final Velocity (v)=11 m/s
Time (t)=600 seconds
Accerlation (a)=?
Use Equation of Motion
v=u+at
11=0+600a
600a=11
a=11/600
a=0.018 m²
Accerlation=0.018 m/s²
pratyush4211:
is that right?tell fast
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