Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40km/hr in 10 minutes. Find its acceleration.

Answer 1

Given:

• Initial velocity (u) = 0 km/h
• Final velocity (v) = 40 km/h
• Time (t) = 10 min

To Find:

• Its acceleration.

Solution:

★ Converting units,

Initial velocity = 0 km/h

⇒ u = 0 × 5/18

⇒ u = 0 m/s

Final velocity = 40 km/h

⇒ v = 40 × 5/18

⇒ v = 11 m/s

Time = 11 min

⇒ t = 11 × 60

⇒ t = 660 s

★ Applying 1st eqn. of motion,

v = u + at

⇒ 11 = 0 + a × 660

⇒ 11 = 660a

⇒ a = 11/660

⇒ a = 0.016 m/s²

Hence:

An acceleration of a train is 0.016 m/s².

Answer 2

$\huge\mathcal\colorbox{skyblue}{{\color{white}{★ANSWER★}}}$

$\huge\color{skyblue}{\textbf{\textsf{GIVEN :-}}}$

• Initial velocity (u) = 0 km/h
• Final velocity (v) = 40 km/h
• Time (t) = 10 minutes

$\huge\color{skyblue}{\textbf{\textsf{TO FIND :-}}}$

• It's Acceleration.

$\huge\color{skyblue}{\textbf{\textsf{SOLUTION :-}}}$

Converting units,

Initial velocity = 0 km/h

=> u = 0 × 5/18

=> u = 0 m/s

Final velocity = 40 km/h

=> v = 40 × 5/18

=> v = 11 m/s

Time = 10 min

=> t = 10 × 60

=> t = 600 s

Applying 1st eqn. of motion,

v = u + at

=> 10 = 0 + a × 600

=> 10 = 600a

=> a = 10/600

=> a = 0.016 m/s²

Hence, the acceleration of a train is 0.016 m/s².

Hope it Helps Buddy ❤️