Question

a train starting from a railway station and moving with uniform acceleration attains a speed 40 kilometre per hour in 10 minutes find its acceleration​

Answer 1

Answer:

Answer:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.)

Final speed of the train, v = 40 km/h = $\frac{5}{18}$ × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ $a=\frac{v-u}{t}$

Solution:-

Putting all the values, we get

⇒ $a=\frac{v-u}{t}$

⇒ $a=\frac{11.11-0}{600}$

⇒ $a=\frac{11.11}{600}$

⇒ $a=0.0185 \: m/s^2$

Hence, Acceleration of the train is 0.0185 m/s².

Answer 2

Question:

A train starting from a railway station and moving with uniform acceleration attains a speed 40 kilometre per hour in 10 minutes. Find its acceleration?

Answer:

According to the question;

Initial velocity of train(u) = 0 m/s

Final velocity of train(v) = 40 km/hr

= 40 × 5/18 m/s

= 11.11 m/s

Total time taken(t) = 10 min

= 10 × 60 sec

= 600 sec

Acceleration of train(a) = ?

We will use the formula to find acceleration:

v = u + at

=> 11.11 = 0 + a×600

$= > a = \frac{11.11}{600}$

=> a = 0.0185 m/s²

So, the acceleration of the train = 0.0185 m/s²