Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40km/h in 10 mins. find its acceleration​

Answer 1

Question : A train starting from a railway station and moving with uniform acceleration attains a speed 40km/h in 10 mins. find its acceleration

Since it started from Railway station, It starts from rest, u = 0

Given,

1. Initial Velocity (u) = 0 kmph
2. Final Velocity (v) = 40kmph
3. Time (t) = 10 min = 1/6 hour

By the equation of motion,

$\: \: \: \: \: \: \boxed{\: a = \frac{v - u}{t} } \:$

$a = \frac{40 - 0}{ \frac{1}{6} } \\ \\ a = {40} \times 6 \\ \\ a = 240 \: kmph$

Acceleration of the train is 240 kmph

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Whenever you see such questions of Kinematics, These 3 equations will help

First equation of motion

• v = u + at

Second equation of motion

• S = ut + ½at²

Third equation of motion

• v² - u² = 2as

Note that,

1. u = Initial Velocity
2. v = final Velocity
3. S = displacement
4. a = Acceleration
5. t = time

Answer 2

Answer:

0.0185 m/second square.

Step-by-step explanation:

As the train started from a railway station, so initial velocity of train, u = 0

Final velocity of train, v = 40 kmph

Final velocity, v = 40 × 5/18 = 11.11 m/s

Assuming uniform acceleration of ‘a’ m/second square

Time taken by train to get it's final velocity, t = 10 minutes = 600 seconds

Using first equation of motion,

V = u + at

11.11 = 0 + a×600

a = 11.11/600 = 0.0185 m/second square.

So, required acceleration , a = 0.0185 m/second square.