Question

A train starting from a railway station and moving with a uniform acceleration attains a speed of 60 km per hour in 15 minutes find its acceleration

Answer 1

Answer:

$\frac{1}{54} m/s^{2}$

Explanation:

Given:

Initial velocity = u = 0 m/s

Final velocity = v = 60 km/hr

60 km/hr = $60 \times \frac{5}{18} =\frac{100}{6} \ m/s$

Time = t = 15 minutes

1 minute = 60 seconds

15 minutes = 15×60=900 seconds

To find:

Acceleration of the train (a)

Using first equation of motion which says:

V=u+at

$\frac{100}{6}=0+a \times900$

$\frac{100}{6} = 900a$

$a = \frac{100}{6} \times \frac{1}{900}$

$a = \frac{1}{54} m/s^{2}$

The acceleration of the train is equal to $\frac{1}{54} m/s^{2}$

Answer 2

Acceleration of train is 0.02 m/s²

Explanation :

Train starting from raway station, so it starts from rest. So, u = 0 m/s

Final speed of train = 60 km/h

⇒ 60 × (5/18) m/s

⇒ 16.67 m/s

Time given = 15 minutes.

⇒ (15 × 60) s

⇒ 900 s

We will use 1st equation of motion to find acceleration :-

⇒ v = u + at

⇒ 16.67 = 0 + a × 900

⇒ 16.67 - 0 = 900a

⇒ 900a = 16.67

⇒ a = 16.67/900

⇒ a = 0.02 m/s²

∴ Acceleration of train = 0.02 m/s²