A train starting from a railway station and moving with a uniform acceleration attains a speed of 40 kmph in 10 minutes. Find its acceleration.
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Answered by
3
soln:
initial velovity= 0m/s
final v= 40km/hr=100/3m/s
time=10 s
acceleration=(100/3-0)/10=10/9 m/s^2
initial velovity= 0m/s
final v= 40km/hr=100/3m/s
time=10 s
acceleration=(100/3-0)/10=10/9 m/s^2
Answered by
13
From the equations of motion,
v = u + a.t ,
Where v = final velocity, u = initial velocity, a = acceleration, t = time.
a = {v-u}/{t}
Given :
v = 40km/hr = 11.11 m/s
u = 0 km/hr (Assuming)
t = 10 minutes = 600 seconds.
Substituting all the values in the above equation,
a = {11.11}/{600} = 0.0185 m/s^2 (or) 240 km/hr^2
v = u + a.t ,
Where v = final velocity, u = initial velocity, a = acceleration, t = time.
a = {v-u}/{t}
Given :
v = 40km/hr = 11.11 m/s
u = 0 km/hr (Assuming)
t = 10 minutes = 600 seconds.
Substituting all the values in the above equation,
a = {11.11}/{600} = 0.0185 m/s^2 (or) 240 km/hr^2
VrindaDubey:
Thank you so much
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