A train starting from a railway station and moving with in uniform acceleration attains a speed 40 km /h in 10 minutes . Find it's acceleration.
Answers
Answered by
1
here see acceleration is equal to slope or gradient of line or curve in velocity time
graph so we can say that the acceleration is equal to change velocity /change in time because of slope is equal to change of y component/change of x component
so in this question change in velocity is equal to 40-0 = 40 km/h because in initial
train is in state
so acceleration= 40km/h÷10min = 40km/h÷1/6h = 240km/h²
graph so we can say that the acceleration is equal to change velocity /change in time because of slope is equal to change of y component/change of x component
so in this question change in velocity is equal to 40-0 = 40 km/h because in initial
train is in state
so acceleration= 40km/h÷10min = 40km/h÷1/6h = 240km/h²
UmmiShabbir001:
The correct answer is 0.0185
First we will have to convert km/he into m/s. Then 11.11/600=0.0185
ok it is solve by change in m/s² from km/h²
But thanks ur logistics are good
sorry i edit it
Answered by
2
u = 0 km/h
v = 40 km/h = 40×1000 = 40000
t = 10 min = 10×60=600
a= v = u+ at
40000 = 0 + a(600)
40000 = 600a
40000/600 = a
a = 66.6 m/s^2
v = 40 km/h = 40×1000 = 40000
t = 10 min = 10×60=600
a= v = u+ at
40000 = 0 + a(600)
40000 = 600a
40000/600 = a
a = 66.6 m/s^2
Wrong
Similar questions