Question

a train starting from A stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes find its acceleration​

Answer 1

Answer:

a= 216 km/hr^2

Step-by-step explanation:

a=?

v=36 km

u=0

t=1/6 hr

v=u+at

36= 0 + a(1/6)

36= a/6

a= 36*6

a= 216 km/hr^2

Answer 2

Answer:

0.01666 $m/s^{2}$

Step-by-step explanation:

u = 0

v = 36 km/h = 10 m/s

time = t =10 minutes = 600 sec

$a = \frac{v- u}{t}$

= 10 / 600

=1/60

= 0.01666 $m/s^{2}$

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