A train starting from one station accelerates uniformly over a distance of 5 km moves with a constant speed of 35 km per uniformly over the last 10 kilometre coming to a stop at another station 50 km away from the first Station travelocity distance graph of the train
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Answer:
here,
intial speed- u=0
- final speed- v=40X 1000
- 60X60
- answer- 11.11
- time taken,t= 10 min = 10X60 =600s
- accerlaration- a= v-u
- t
- 11.11-0 = 1.8X10 -2m/s
- 600
- final speed - 11.11
- acceleration- 2m/s
- hope it will help you
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