a train starting from railway station and moving with uniform acceleration attains a speed 40 km/h-¹ in 10 minutes .find the acceleration
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Answered by
9
if 40 km/hr then
v=40km/h =(40*1000/60*60*1)m/s
=40000/3600)m/s.
=11.11m/s
u=0m/s
time (t)=10*60 sec=600 sec
a=v-u/t =11.11-0/600
=0.0185m/s2
v=40km/h =(40*1000/60*60*1)m/s
=40000/3600)m/s.
=11.11m/s
u=0m/s
time (t)=10*60 sec=600 sec
a=v-u/t =11.11-0/600
=0.0185m/s2
Answered by
2
Answer:
U=0 as the train was in rest
v=40km/hr=40*5/18=100/9 m/s=11.1m/s
t=10 min=10*60=600sec
a=v-u/t
=11.1-0/600
=111/6000 m/s
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