Question

a train starting from railway station and moving with uniform acceleration attains a speed of 40km/hr in 15 mins . find the acceleration .

Answer 1

hey dear
here is your answer

given data :

initial velocity (u) = 0

final velocity (v) = 40 km/hr or 11.12 m/s

time taken (t) = 15 min. or 900 seconds

to find : acceleration

here we go

solution :

by using first equation of motion

v = u+at

11.12 = 0+900a

a = 11.12/900

a = 0.0123 m/s²

hope it helps :)

Answer 2

Hey.

Here is the answer.

starting from rest ,so u=0 m/s
v = 40 km/h = 40×5/18 m/s = 200/18 m/s
t = 15 minutes = 15×60= s =900 s

As, v= u + a t

so, 200/18 =0 +a × 900

or, 200/18 = 900 a

or, a = 200/ 18×900 = 1 / 81 m/s^2= 0.01234 m/s^2

Thanks.