Question

a train starting from railway station and moving with uniform acceleration attains a speed 40km/h in 10minutes. find its accleration

Answer 1

U=0, v=40km/h, t1/6hr, v=u+at, 40=0+a1/6, a=240, Initial velocity (u) = 0, Final velocity (v) =40km/hr = 40 multiple by 5/18 m/s = 100/9 =11.11 m/s, Time (t) = 10 min= 10 multiple with 60 s= 600 s.

Therefore Acceleration = final velocity initial velocity / time taken=11.11 0 / 600 m/s sq= 0.0185 m/s sq.

Answer 2

here is your answer -

Acceleration - Rate of change of velocity with respect to time is known as acceleration.

according to question -

initial velocity (u) = 0 (as train starts from rest)

final velocity (v) = 40 km/h

time taken (t) = 10 min.
t = 10 × 1/60 hr
t = 1/6 hr

This is the case of accelerated motion so, we have to use equation of motion.

v = u + at

40 km/hr = 0 + (1/6 hr × a)

40 km/hr = a/6 hr

a = 40 km/hr × 6 hr

a = 240 km/hr^2

So, the acceleration of the train is 240 km/hr^2

thanks !!!