A train starting from railway station and moving with a uniform accelaratiin and attains a speed of 40km/hr in 10 minutes find the accelaration?
Answers
Answered by
4
Hey Mate here is your answer
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Here
Initial velocity (u) = 0
Final velocity (v)=40km/hr
= 40 multiple by 5/18 m/s
= 100/9
=11.11 m/s
Time (t) = 10 min
= 10 multiple with 60 s
= 600 s
Therefore
Acceleration = final velocity — initially velocity / time taken
=11.11 — 0 / 600 m/s sq
= 0.0185 m/s sq
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SHIVANI SAHGAL
------------------------------------------
Here
Initial velocity (u) = 0
Final velocity (v)=40km/hr
= 40 multiple by 5/18 m/s
= 100/9
=11.11 m/s
Time (t) = 10 min
= 10 multiple with 60 s
= 600 s
Therefore
Acceleration = final velocity — initially velocity / time taken
=11.11 — 0 / 600 m/s sq
= 0.0185 m/s sq
---------------------------------------
---------------------------------------
SHIVANI SAHGAL
Answered by
2
time =10min
= 10×1/60 hrs
=1/6 hrs
acceleration =speed/time
=40÷1/6
=40×6
=240
= 10×1/60 hrs
=1/6 hrs
acceleration =speed/time
=40÷1/6
=40×6
=240
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