Question

A train starting from railway station attains a speed of 45 m/s in 2 minute. Find its acceleration.​

Answer 1

Answer:

Answer:

Given parameters

Initial velocity (u) = 0

Final velocity (v) = 40 km/h

v = 40 × (5/18)

v = 11.1111 m/s

Time (t) = 10 minute

t = 60 x 10

t = 600 s

Acceleration (a) =?

Consider the formula

v = u + at

11.11 = 0 + a × 600

11,11 = 600 a

a = 11.11/600

a = 0.0185 ms-2

Answer 2

Explanation:

Given: t=10 min=10×60=600s

Initial speed of train is given as: u=0 ms−1

Final speed of train is given as: v=40 km h−1=360040×1000=11.1 ms−1

Now acceleration is given by the relation:

a=tv−u=60011.1−0=0.0185 ms−2