Question

A train starting from rest, accelerates uniformly and attains a velocity 48 kmh-1 in 2 min. It travels at this speed for 5 minutes. Finally, it moves with uniform retardation and is stopped after 3 min. Find the total distance travelled by the train?

Answer 1

Explanation:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

Answer 2

Answer:

3km

Explanation:

0+(1/2)(1/15)(300)(300)

3km