Question

A train starting from rest acquires a velocity of 72 km/h in 0.2 minutes. The

acceleration of the train is:


A. 1.27 m/s2

B. 1.67 m/s2
C. 2.67 m/s2

D. None of the above​

Answer 1

Answer:

v=u+at

a=(v-u)/t

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km