Question

a train starting from rest aculeratise 120km/hrs is 1 min in a straight path calculate average acceleration​

Answer 1

Explanation:

v=120km/hr = 120 * 1000/3600 m/s= 33.33 m/s

u=0m/s as it started from rest

a=(v-u)/t

=(33.33-0)/60

=100/180

=0.556 m/s2