a train starting from rest and attains a velocity of 72 km per hour in 5 minutes. assuming that the acceleration is uniform find a) acceleration b) distance travelled by the train for attaining this velocity.
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Explanation:
Given initial velocity, u = 0 m/s (since the train is starting from rest)
final velocity, v = 72 km/h = 72×1000/60×60=20 m/s
time taken, t = 5 min = 5×60s = 300s
Therefore a= (v-u)/t=(20-0)/300=2/30=1/15 m/s²
distance, s = ut + at²/2=at²/2
=1×300²/15×2=30×10×300/30=3000 m = 3km
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