A train starting from rest and moving with a uniform acceleration attains a speed of 9p km/h in 5 min. The acceleration is
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Answer:
train start from rest then u=o
time given is 5 min = 5×60 = 300 sec
final velocity v= 9×5/18= 2.5 m/s
formula a=v-u/t
= 2.5/300 = 0.008 m/s2
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