a train starting from rest and moving with uniform acce. attains a speed of 90km/hr in 5 min find acc and dist. travelled
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Explanation:
Given that :-
Initial velocity u = 0
Final velocity v = 90km/ hr = 25 m/s
and time = 5min = 5 * 60 = 300 sec.
We know that V = U + AT ---------------( 1 )
25 = 0 + A * ( 300 )
A = 25 / 300 = 1 / 12
A = 0.833 m/s ✅
We know that distance = speed * time
= 25 * 300
= 7500 metre ✅
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