A train starting from rest aquires a velocity of 54km/hr in 20 secs . calculate the acceleration and distance travelled by it.
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final velocity= 54Km/h = 15m/s
time= 20 sec
initial velocity = 0
v= u + at
15 = 0 + a(20)
a = 15/20
a= 3/4 m/s^2
now, from the following equation-
v^2 = u^2 + 2aS
(15)^2 = 0 + 2(3/4)S
225= (3/2)S
S = 225*2/3
S = 150m
time= 20 sec
initial velocity = 0
v= u + at
15 = 0 + a(20)
a = 15/20
a= 3/4 m/s^2
now, from the following equation-
v^2 = u^2 + 2aS
(15)^2 = 0 + 2(3/4)S
225= (3/2)S
S = 225*2/3
S = 150m
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