A train starting from rest aquires a velocity of 54km/pr in 20 sec . Cal ulate the acceleration and distance travelled by it
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Hello Friend,
Here,
→ The train starts from rest. This means that initial velocity must be zero. Next, we need to convert all units into SI units. So, we will convert 54 km/h into m/s
Initial velocity = u = 0 m/s
Final velocity = v = 54 km/h = 15 m/s
Time = t = 20 s
Let acceleration be a.
Let distance travelled be s.
→ Now, motion is uniformly accelerated. So,
v = u + at
So, 15 = 0 + a(20)
So, a = 15/20 m/s²
So, a = ¾ m/s²
Or, a = 0.75 m/s²
→ Now, to find the distance travelled,
s = ut + ½ at²
So, s = (0)(20) + (½)(¾)(20)²
So, s = ⅜ × 400
So, s = 150 m
→ Thus, acceleration is 0.75 m/s² and distance travelled is 150 metres.
Hope it helps.
Purva
@Purvaparmar1405
Brainly.in
Here,
→ The train starts from rest. This means that initial velocity must be zero. Next, we need to convert all units into SI units. So, we will convert 54 km/h into m/s
Initial velocity = u = 0 m/s
Final velocity = v = 54 km/h = 15 m/s
Time = t = 20 s
Let acceleration be a.
Let distance travelled be s.
→ Now, motion is uniformly accelerated. So,
v = u + at
So, 15 = 0 + a(20)
So, a = 15/20 m/s²
So, a = ¾ m/s²
Or, a = 0.75 m/s²
→ Now, to find the distance travelled,
s = ut + ½ at²
So, s = (0)(20) + (½)(¾)(20)²
So, s = ⅜ × 400
So, s = 150 m
→ Thus, acceleration is 0.75 m/s² and distance travelled is 150 metres.
Hope it helps.
Purva
@Purvaparmar1405
Brainly.in
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