Question

a train starting from rest attain a velocity of 72 km/h in 5min. assuming that the acceleration is uniform,find a) the acceleration and b) the distance travelled by the train for attention this velocity​

Answer 1

ANSWER

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km