Question

A train starting from rest attain its velocity at 20 m/s in 5 minutes if the acceleration is 1/15 m/s² then find the distance travel during this time??

Answer 1

Answer:

$\huge{\underline{\underline{\mathbb{\red{Answer:-}}}}}$

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

Answer 2

$\huge{ \underline{ \pmb{ \red{here \:is \: ur \: answer}}}}$

$\Rightarrow \: {initial \: velocity = 0}$

$\Rightarrow \: { final \: velocity = 20 \frac{m}{s} }$

$\Rightarrow \: {time = 2min = 120sec}$

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$1)acceleration = \: ?$

$\pmb{using \: first \: equation}$

$\boxed{ \pmb{ \purple{v = u + at}}}$

$\rightarrow \: {20 = 0 + 120a}$

$\rightarrow \: {20 = 120a}$

$\rightarrow \: a = \frac{20}{120}$

$\rightarrow \: {a = \frac{1}{6} }$

$\boxed{a = 0.167 \frac{m}{ {s}^{2} } }$

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$2)distance \: travelled = \: ?$

$\pmb{using \: third \: equation}$

$\boxed{ \pmb{ \purple{ {v}^{2} = {u}^{2} + 2as}}}$

$\rightarrow \: { {20}^{2} = {0}^{2} + 2 \times 0.167 \times s}$

$\rightarrow \: {400 = 0.334 \times s}$

$\rightarrow \: {s = \frac{400}{0.334} }$

$\boxed{s = 1197.6m}$