Question

A train starting from rest attains a velocity of 108km/h in 2 minutes.Assuming the accleration to uniform find the value of - 1.accleration 2.distance covered.

Answer 1

distance = speed into time
108km=108000m
2min=120sec
1.
$a = (v - u) \div t$
a =108000-0/120
a=900m/s^2

distance=speed ×time
=108×2
=216