Question

A train starting from rest attains a velocity of 108Kmh-1

in minutes. Assume that the

acceleration is uniform. Find

a) the acceleration b) the distance travelled by the train for attaining this velocity​

Answer 1

Correct Question :

A train starting from rest attains a velocity of 108 km/h in 10 minutes. Assume that the acceleration is uniform. Find a) the acceleration b) the distance travelled by the train for attaining this velocity.

Answer :

Given :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 108 km/h = 30 m/s
• Time (t) = 10 minutes = 600 seconds

To find :

• Acceleration (a) &
• Distance (s)

According to the question,

→ v = u + at

Where,

• v stands for Final velocity
• u stand for Initial velocity
• a stands for Acceleration
• t stands for Time

→ Substituting the values,

→ 30 = 0 + a × 600

→ 30 - 0 = 600a

→ 30 = 600a

→ 30 ÷ 600 = a

→ 0.05 = a

.°. The acceleration is 0.05 m/s²..

Now,we will calculate distance :-

→ s = ut + ½ at²

Where,

• s stands for Distance
• u stand for Initial velocity
• a stands for Acceleration
• t stands for Time

→ s = 0 × 600 + ½ × 0.05 × 600 × 600

→ s = 0 + 5 × 1800

→ s = 9000 m

.°. The distance is 9000 m..

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