Question

A train starting from rest attains a velocity of 144 km / h in 5 minutes assuming that acceleration is uniform said acceleration by the train for attaining this velocity

Answer 1

Heya!

Here's your answer>>

Initial velocity = u = 0 
Final velocity = v = 144 km/h 
time = t = 5 mins = 1/12hr 

Acceleration = v - u/t 
= 144 - 0 ÷ 1/12 
= 144 × 12
= 1728 km/h 

Ans: The acceleration of the body is 1728 km/h. 

Hope helped!!

Answer 2

Given:

Initial velocity (u) = 0

Final velocity (v) = 144km/hr

Time taken (t) = 5 min = 1/12 hr

i) Acceleration:

We know that,

Acceleration=(v−u)

t

⟹ a = (144 - 0) / (1/12)

⟹ a = 144 / (1/12)

s⟹ a = (144 × 12) / 1

⟹ a = 144 × 12

⟹ a = 1728 km/hr²

Therefore, acceleration = 1728 km/hr²

ii) The distance travelled by the train for attaining this velocity:

s=ut+2/1 at

⟹ s = 0 × (1/12) + 1/2 × 1728 × (1/12)²

⟹ s = 1 × 864.5 x 144

⟹ s = 124488

Therefore, distance = 124488 km

Answer by : Eric