Question

A train starting from rest attains a velocity of 20 m/s in 300 s. If the acceleration is uniform, then the distance travelled by the train for attaining this velocity is
1 point
a. 6000 m
b. 1500 m
c. 3000 m
d. 1000 m

Answer 1

Answer:

C. 3000m

Explanation:

We know that acceleration = (final velocity - initial velocity)/ time

- a = (20 - 0)/300 = 1/15 m/s^2

- now use formula: S = ut + 1/2 at^2

since, train starts from rest so it's initial velocity is 0

- S = 0 + (1/2)*(1/15)*300*300 = 3000m