a train starting from rest attains a velocity of 20m/s in 2 min. assuming that the acceleration is uniform, find (1) the acceleration (2) distance travelled by the train, while it attained this velocity
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Answer:
(1)1/6m/s^2
(2)2400m
Explanation:
u=0 m/s
v=20 m/s
t=2 min=120 s
(1)acceleration=(v-u)/t
=(20-0)/120
=20/120
=1/6 m/s^-2
(2)distance=speed×time
=20×120
=2400m
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