Question

a train starting from rest attains a velocity of 20m/s in 2 minutes. assuming that the acceleration is uniform, find
1 the acceleration
2 distance travelled by the train, while it attained this velocity.

Answer 1

hey dear
here is yuour answer

initial velocity = 0
final velocity = 20 m/s
time = 2 min.= 120 seconds

1) acceleration = ?

so, by using 1st equation of motion

v = u+at
20 = 0+120a
a = 20/120 = 1/6 = 0.167 m/s²

2) distance travelled = ?

by using thurd equation of motion

v² = u²+2as
(20)² = 0+2*0.167*s
400 = 0.334s
s = 400/0.334 = 1197.6 meter

hope it helps :)

Answer 2

1. as we know acceleration equals change in velocity upon time taken.
Now as we know train started from rest therefore its initial velocity is zero and final velocity is 20 m per second and time taken is 2 minutes that is 60×2=120sec.
Now let's solve 20 - 0/120=20/120=6m/s^2
2. now as we know speed = distance upon time therefore distance =speed into time.
Therefore, 20×2=40m is the dist