A train starting from rest attains a velocity of 20m/s in 2 min . Assuming that the acceleration is uniform find
1- the acceleration
2- distance traveled by the train while it attained this velocity.
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2min=120s
Acceleration=(v-u)/t
=(20-0)/120
=1/6m/s^2
distance travelled=s=ut+1/2at^2
=0+1/2*1/6*120*120
=1200m
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Acceleration=(v-u)/t
=(20-0)/120
=1/6m/s^2
distance travelled=s=ut+1/2at^2
=0+1/2*1/6*120*120
=1200m
Please mark as brainleist.
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