A train starting from rest attains a velocity of 20m/sec in 2 minutes. Assuming that the acceleration is uniform,find: (a) The acceleration. (b) distance travelled by the train while it attains the velocity.
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v=20m/s
u=0m/s
t=2minute=>120second
a=v-u/t
=20-0/120
=20/120
=1/6m/s
S=ut+1/2at²
=(0×120)+1/2×1/6×120²
=0+1/2×1/6×120²
=1200mtr
u=0m/s
t=2minute=>120second
a=v-u/t
=20-0/120
=20/120
=1/6m/s
S=ut+1/2at²
=(0×120)+1/2×1/6×120²
=0+1/2×1/6×120²
=1200mtr
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