Question

a train starting from rest attains a velocity of 25m/s in 600s. assuming that the acceleration is uniform, find the acceleration and the distance travelled by the train while it has attained this velocity.

Answer 1

Given,

Initial Velocity = 0

Final Velocity = 25 m/s

Time = 600 s

=> v = u+at

=> 25 = 0 + a x 600

=> 25/600 = a

=> a = 0.0416 m/s^2


Again,

=> S = ut+ 1/2 at^2

=> S = 0 + 1/2 x 0.416 x 600 x 600

=> S = 74988 m

or

=> S = 74988/1000 Km = 74.988 Km



Be Brainly

Answer 2

To Find:-

• Find the acceleration and the distance travelled by the train.

Given:-

• Train starts from rest and attains a velocity of 25 m/s in 600 sec.
• Assume that the acceleration is uniform.

Solution:-

Let the acceleration be " a "

The distance travelled be " s "

Here,

️ ➭ u = initial velocity

️ ➭ v = final velocity

️ ➭ a = acceleration

️ ➭ s = distance

️ ➭ t = time

Now,

u = 0 ; v = 25m/s ; t = 600sec ; s = ? ; a = ?

️ ➭️ v = u + at

️ ➭ 25 = 0 + 600a

️ ➭ 25 = 600a

️ ➭ a = 25/600

️ ➭ $\tt { \: a \: = \: 0.041m/s² \: }$

Now,

️ ➭ s = ut + 1/2 at²

️ ➭ s = 1/2 × 0.041 × 600 × 600

️ ➭ s = 0.041 × 300 × 600

️ ➭ $\tt { \: s \: = \: 7380m \: }$