Question

A train starting from rest attains a velocity of 30 metre per second in 10 seconds find number one acceleration number to distance travelled by the train for the attending the velocity

Answer 1

Answer:

initial velocity = 0

final velocity = 20 m/s

time = 2 min.= 120 seconds

1) acceleration = ?

so, by using 1st equation of motion

v = u+at

20 = 0+120a

a = 20/120 = 1/6 = 0.167 m/s²

2) distance travelled = ?

by using thurd equation of motion

v² = u²+2as

(20)² = 0+2*0.167*s

400 = 0.334s

s = 400/0.334 = 1197.6 meter