A train starting from rest attains a velocity of 36 km/ h in 10 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and (ii) the distance travelled by the train for attaining this velocity.
Answers
Explanation:
Given:-V (final velocity) = 36 km/h
= 36×5/18 m/ s
= 10 m/s.
u (final velocity) = O m/s
time = 10 minutes = 10× 60 second = 600 second
( 1 ) -} a ( acceleration) = v - u
--------
t
= 10-0/600
= 10/600
= 0.016 m/s² ( approx).
( 2 ) -} Distance = speed / time
= 10 / 600 = 0.016 m.
Answer:
i)the acceleration of a train vehicle moving from zero to 36 km/h in 10 minutes is 0.06 m/s²
ii)The train would travel 0.016 m in order to accomplish this distance.
Explanation:
Here, velocity = 36 km/ h
v=36km/ h
= 36×5/18 m/ s
= 10 m/s.
u (final velocity) = O m/s
time = 10 minutes = 10× 60 second = 600 second
Next,
acceleration= v - u
= 10-0/600
= 10/600
= 0.016 m/s² ( approx).
Distance = speed/time
= 10 / 600 = 0.016 m.
The accurate measurement of an object's location and speed is its velocity. It is the distance that even an object travels from one unit of time. The displacement of the particle in one unit of time is the definition of velocity.
Distance is the aggregate of an object's motion, disregarding direction. The distance can be defined as the total amount of territory an object has covered, disregarding of its starting or ending location.
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