A train starting from rest attains a velocity of 36km/hr in 10 min. Assuming that acceleration is uniform. Find(i) acceleration(ii) the distance travelled by the train for attaining this velocity.
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v=36km/hr=10m/sec
u=0
t=10min=600sec
a=v-u/t
a=1/60 m/sec^2
s=ut+1/2at^2
s=1/2x1/60x600x600
s=3000m
u=0
t=10min=600sec
a=v-u/t
a=1/60 m/sec^2
s=ut+1/2at^2
s=1/2x1/60x600x600
s=3000m
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